{"id":16938,"date":"2024-04-30T16:43:23","date_gmt":"2024-04-30T16:43:23","guid":{"rendered":"http:\/\/dudoanlosongthu.com\/?p=16938"},"modified":"2024-04-30T16:43:23","modified_gmt":"2024-04-30T16:43:23","slug":"du-doan-xo-mien-bac-tinh-ngay-bach-thu-hom-nay","status":"publish","type":"post","link":"https:\/\/dudoanlosongthu.com\/du-doan-xo-mien-bac-tinh-ngay-bach-thu-hom-nay\/","title":{"rendered":"D\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc t\u00ednh ngay b\u1ea1ch th\u1ee7 h\u00f4m nay"},"content":{"rendered":"

B\u1ea1n s\u1ebd c\u00f3 ngay nh\u1eefng con s\u1ed1 b\u1ea1ch th\u1ee7 ch\u00ednh x\u00e1c n\u1ebfu hi\u1ec3u v\u00e0 \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc<\/strong> d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n

1. C\u00e1ch d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc b\u1eaft l\u00f4 t\u1ed5ng.<\/strong><\/h3>\n

Quan s\u00e1t v\u00e0o h\u00e0ng 3 s\u1ed1 gi\u1eefa c\u1ee7a gi\u1ea3i 5 v\u00e0 6. C\u00e1ch b\u1eaft nh\u01b0 sau:
\nGi\u1ea3i 5: G2.4 v\u00e0 G5.4 k\u1ebft h\u1ee3p Gi\u1ea3i 6: G2.3 ng\u00e0y 17\/10 ta c\u00f3 3 s\u1ed1 t\u1ed5ng l\u00e0 7+7+5=19. Ta \u0111\u00e1nh c\u1eb7p 191<\/p>\n

\u00c1p d\u1ee5ng v\u1edbi d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc<\/strong> nu\u00f4i khung 3 ng\u00e0y.<\/p>\n

2. C\u00e1ch d\u1ef1 \u0111o\u00e1n b\u1eaft l\u00f4 h\u00ecnh tam.<\/strong><\/h3>\n

Quan s\u00e1t v\u00e0o Gi\u1ea3i 5 v\u00e0 6 c\u1ee5 th\u1ec3 nh\u01b0 sau:
\nGi\u1ea3i 5: G6.3 nh\u00ecn l\u00ean, Gi\u1ea3i 5 G3.4 nh\u00ecn xu\u1ed1ng, gi\u1ea3i 6 G3.3 c\u1ee5 th\u1ec3 trong ng\u00e0y 17\/10 ta s\u1ebd c\u00f3 s\u1ed1 1, 9 v\u00e0 5.<\/p>\n

C\u00e1ch d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> n\u00e0y th\u01b0\u1eddng \u00e1p d\u1ee5ng cho \u0111\u00e1nh l\u00f4 t\u00f4 b\u1ea1ch th\u1ee7. Gi\u1ea3i 5 G3.4  v\u1edbi Gi\u1ea3i 6 G3.3 tr\u00f9ng s\u1ed1 th\u00ec ta l\u1ea5y s\u1ed1 \u1edf gi\u1eefa l\u00e0m t\u00e2m \u0111i\u1ec3m quan s\u00e1t.<\/p>\n

Nu\u00f4i s\u1ed1 trong 3-5 ng\u00e0y.<\/p>\n

3. C\u00e1ch <\/strong>d\u1ef1 \u0111o\u00e1n<\/strong> b\u1eaft l\u00f4 ch\u1ea1m 2 nh\u00e1y.<\/strong><\/h3>\n

C\u00e1ch n\u00e0y kh\u00f4ng c\u1ea7u k\u1ef3 b\u1edfi \u0111\u1ec3 \u00fd h\u00f4m qua c\u1eb7p n\u00e0o v\u1ec1 2 nh\u00e1y th\u00ec nay \u0111\u00e1nh ch\u1eb7n \u0111\u1ea7u \u0111u\u00f4i c\u1ee7a c\u1eb7p \u0111\u00f3.<\/p>\n

V\u00ed d\u1ee5: v\u1ec1 2 nh\u00e1y 46 th\u00ec ta \u0111\u00e1nh 45 v\u00e0 47 cho h\u00f4m sau. C\u00e1ch n\u00e0y max d\u1ec5 ch\u01a1i l\u1ea1i kh\u00e1 hi\u1ec7u qu\u1ea3 cho vi\u1ec7c h\u1ed7 tr\u1ee3 ch\u1ecdn s\u1ed1.<\/p>\n

\"du
B\u1ea1ch th\u1ee7 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc<\/figcaption><\/figure>\n

4. C\u00e1ch d\u1ef1 \u0111o\u00e1n b\u1eaft l\u00f4 tr\u00f9ng c\u1eb7p.<\/strong><\/h3>\n

Quan s\u00e1t v\u00e0o Gi\u1ea3i 2 G1. N\u1ebfu th\u1ea5y k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 v\u1ec1 c\u00f3 d\u1ea1ng ch\u1ecdn \u0111\u1ea7u ch\u1ecdn \u0111\u00edt. V\u00ed d\u1ee5 nh\u01b0 ng\u00e0y h\u00f4m kia c\u00f3 26404 t\u1ee9c l\u00e0 d\u1ea1ng s\u1ed1 chia ra c\u00f3 c\u1eb7p 040 v\u00e0 s\u1ed1 26. V\u1edbi s\u1ed1 nh\u01b0 v\u1eady ta kh\u00f4ng b\u1eaft 040 nh\u00e9 m\u00e0 ch\u1ecdn \u0111\u01b0\u1ee3c c\u1eb7p 262 cho khung 3 ng\u00e0y.<\/p>\n

Tr\u01b0\u1eddng h\u1ee3p kh\u00f3 ch\u1ecdn s\u1ed1 nh\u01b0 c\u00f3 d\u1ea1ng s\u1ed1 48888 ho\u1eb7c 88848 nh\u01b0 th\u1ebf n\u00e0y ta c\u00f3 th\u1ec3 \u0111\u00e1nh 04, 40. N\u1ebfu s\u1ed1 c\u00f3 d\u1ea1ng 33848 ho\u1eb7c 84338 ta l\u1ef1a ch\u1ecdn \u0111\u00e1nh s\u1ed1 32 v\u00e0 34. B\u1eb1ng c\u00e1ch n\u00e0y c\u00f3 th\u1ec3 ta s\u1ebd r\u1ea5t d\u1ec5 \u0103n k\u1ebft qu\u1ea3 2 nh\u00e1y tr\u00ean 1 c\u1eb7p \u0111\u00f4i.<\/p>\n

5. C\u00e1ch d\u1ef1 \u0111o\u00e1n b\u1eaft l\u00f4 \u0111\u01b0\u1eddng th\u1eb3ng.<\/strong><\/h3>\n

Quan s\u00e1t v\u00e0o Gi\u1ea3i 3 G2.3 + Gi\u1ea3i 3 G4.3  v\u00e0 Gi\u1ea3i 6 G2.2 nh\u01b0 ng\u00e0y h\u00f4m nay ta c\u00f3 t\u1ed5ng b\u1ed9 s\u1ed1 c\u1ee7a 3 s\u1ed1: 4+3+3=10.<\/p>\n

Nh\u01b0 v\u1eady l\u00e0 c\u00e1c b\u1ea1n \u0111\u00e3 ch\u1ecdn \u0111\u01b0\u1ee3c c\u1eb7p 101 \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc<\/em><\/a>.<\/p>\n

Mu\u1ed1n nh\u1eadn s\u1ed1 li\u1ec1n tay h\u00e3y li\u00ean h\u1ec7 ngay v\u1edbi ch\u00fang t\u00f4i. Nh\u1eefng con s\u1ed1 khoa h\u1ecdc v\u1edbi x\u00e1c su\u1ea5t v\u1ec1 cao nh\u1ea5t s\u1ebd \u0111\u01b0\u1ee3c chuy\u1ec3n ngay t\u1edbi b\u1ea1n. Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng.<\/p>\n

 <\/p>\n

SOI C\u1ea6U MI\u1ec0N B\u1eaeC SI\u00caU CHU\u1ea8N <\/span><\/h3>\n
\n